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Post by Dizzy D on Feb 24, 2017 9:12:42 GMT -5
The only I just can readily recall is Charles Francis Xavier (which I can recall because Franciscus Xavier).
Well, that one and Nathan Christopher Summers (which I can recall, because I know which two characters he's named after).
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Post by Dizzy D on Feb 24, 2017 7:30:04 GMT -5
Don't know if I posted it here or in another thread/board, but I worked my way through the first volume of the Black Monday Murders and I really enjoyed. A pretty dense read where I had to go back to some information given in the first chapter to check how things were supposed to work from time to time but eagerly awaiting more.
In short: there is a connection between the financial world and magic. A small group of hermetic mage bloodlines follow a system where they manipulate the market for financial profit, power and extra years of life, but the system is dangerous and should the market crash, somebody needs to be sacrificed.
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Post by Dizzy D on Feb 15, 2017 7:31:47 GMT -5
Those issues of Thorgal were very much not standalone. What happened previously was that Thorgal was basically cursed by the gods to keep getting dragged into adventures and dangers, which endangered his family as well. In an earlier issue Thorgal manages to change his destiny by erasing himself from the god's memory, but this also erased his own mind. Kriss of Valnorr, his sometimes enemy, saw this opportunity and convinced the amnesiac Thorgal that he is a pirate and her lover. (Thorgal's plan backfired btw, because his family is now enslaved by Kriss)
I need to reread it, but I don't the timetraveller was an older version of Jolan, just somebody who needs the crown.
So you basically are reading the middle act of a longer story.
When I get home, I'll give it a reread to see if I can get the details correctly.
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Post by Dizzy D on Feb 13, 2017 2:37:48 GMT -5
That's basically it, they can infer a bit more information per step: Step 1: The first time Doug answers no, Kitty knows that Doug's number must be less than 54, otherwise, there would have been no reason for him not to directly know the right answer. So Doug's number is more than 0 and less than 54. Step 2: The first time Kitty answers no, Doug knows that like his number, Kitty's must be less than 54 (for the same reason as he didn't know), but also more than 19 (the difference between 88 and 73), because if her number was less than that, 88 would not have been a possibility (as Doug's number must be less than 54 as they realised in step 1). So Kitty's number is more 19 and less than 54. Step 3: Even knowing that Kitty's number must be more than 19, Doug can't answer, so Doug's number must be less than 35 (54-19), otherwise he would have known the answer because if his number is higher than 54 can no longer be a valid sum.
From that point in each step just narrows down the range of the numbers, raising either the lower limit (for Kitty's number) or lowering the top limit (for Doug's number) by 19 for each step.
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Post by Dizzy D on Feb 10, 2017 8:31:17 GMT -5
Another math riddle, with a comic twist this time.
Professor X asks his two best students to the front of the class. Kitty and Doug appear and Xavier asks them both to think of a whole, positive number between 0 and 100. They both do.
Xavier then goes to the blackboard and writes down two numbers on it: 54 and 73. He tells them that 1 of these numbers is the sum of both their numbers.
He asks Doug if he knows what Kitty's number is. Doug replies: "No." He then asks Kitty if she knows what Doug's number is. Kitty also replies: "No." Xavier gives them a few minutes to think about it. He asks Doug again, but Doug still does not know. He then asks Kitty and Kitty replies that she knows that Doug's number is 21.
How did she figure it out?
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Post by Dizzy D on Feb 10, 2017 7:24:28 GMT -5
I don't know if they have a special type of name. It's basically just maths with a small story around it. I haven't seen any version like the one you describe, but I have seen the pirate puzzle with far more pirates than there is gold, at which point you no longer want to be first in line, because there is no offer the first X pirates can make that will please 50% of the pirates, even if they don't take any gold themselves. (For instance 10 gold pieces and 25 pirates, than 4 pirates are getting killed and the next one will chose no gold for himself and 10 pirates get 1 gold, just to stay alive).
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Post by Dizzy D on Feb 8, 2017 6:23:12 GMT -5
It's been a week, so
Solution to the Pirate Puzzle:
I number the pirates by their ages: 21, 25, 30, 34 and 40, to make this easier.
The youngest pirate (21) knows that when it comes down to just him and 25, he will get nothing.
30 realises this as well, so he will offer 21 1 piece of gold and keep the rest himself (21 rather has the 1 piece of gold than get nothing, 25 will disagree but is outvoted.)
34 knows this as well and takes it a step further: if he gets 25 on his side, he can get the votes to stay alive. So he offers 25 1 gold and takes the rest himself.
Finally 40 figures out that he needs 21 and 30 on his side, he offers both of them 1 gold. 21 and 30 realise that they rather have 1 gold than the situation where 34 and 25 get the gold, so they accept.
So the final answer is: Make sure you're first in line and give the rest just the minimum, which is more than they would get from the next person in line.
Solution to The King and the Chairman:
The Chairman wants to get more money, but realises that he needs to initially sacrifice his own wages. He offers 33 people 2 gold/week (33 including the chairman, will get nothing, but the chairman does not get to vote so 32 votes against) > motion is passed.
Basically continue from there, half+1 will get double their wages, the other half gets nothing. (17 for, 16 against; 9 for, 8 against; 5 for, 4 against, 3 for, 2 against and finally 2 in favour, 1 against.)
The Chairman's final motion will be to offer 1 gold/week to 3 people who at that point will be getting nothing, 0 gold/week to the final 2 and the rest to himself (63 gold/week).
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Post by Dizzy D on Feb 8, 2017 5:57:19 GMT -5
Not sure if this is the exact right place for this, but I figured I'd start here and see if it works. Has anyone built a Raspberry Pi? I love the old-school games from Atari, Nintendo, and Sega, but as I was not able to score an NES Classic for Christmas, I've been investigating alternate options for getting access to the generation of games I like and came across the Raspberry Pi. My biggest question, if anyone has done it, is the difficulty level, both in acquiring the components as well as the actual assembly. I'm fairly handy, so unless it requires expert-level skill, I should be OK, but I wanted to get feedback from anyone who has actually done it. I had Raspberry Pi., but an old one (version 2). Didn't use it for games though. Assembly wasn't very difficult (then again I work in IT, so I've maybe a weird view on what's difficult or not).
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Post by Dizzy D on Feb 6, 2017 7:23:24 GMT -5
I like Origins as well, the fighting system is not as smooth as the main series, but the boss fights and the detective parts I like a lot. I also liked that some non-Joker villains get a chance to shine.
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Post by Dizzy D on Feb 2, 2017 5:04:44 GMT -5
I think I wanna be 25 and propose that I get all the gold. You're on the right track, but keep this in mind: 21 knows that if it comes down to 25 and himself, he won't be getting anything, so if 30 makes him an offer... (and work your way back from that.) This is a similar riddle: The King and the ChairmanRiddletania is a small country in Europe with a massive population of 66 people (1 King and 65 peasants). After a revolution, the King agrees to reforms. In the new system, every citizen has a vote except for the King, who will now have the title of Chairman. The Chairman does have the power to propose laws, but citizens need to vote on it. The King received 66 gold per week in taxes, but has agreed to divide this evenly amongst all citizens. In the new system, every citizen, including the Chairman will get a salary of 1 gold piece per person per week. (This is the budget, so the Chairman can't suggest proposals that will spend more than 66 gold/week. No deficits allowed.) - Citizens will vote for any plan that gets them more gold. - Citizens will vote against any plan that gets them less gold. - Citizens won't bother to vote if a new law won't affect them personally. - Citizens are short-sighted and not vindictive, they will vote for any law in isolation based on the previous 3 principles. In this perversion of communism, what is the maximum amount of money the Chairman can get for himself?
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Post by Dizzy D on Feb 1, 2017 8:50:22 GMT -5
Another classic riddle that people will probably know. So if you already know it, give somebody else a chance first:
The Pirate Puzzle
After capturing a ship at heavy losses, 5 pirates survive without their captain. The pirates find a chest aboard the ship with 100 golden coins.
So the pirates will divide the spoils according to pirate tradition:
The oldest pirate will propose a way to divide the spoils (just for sake of clarity, the pirates are aged 21, 25, 30, 34 and 40. They don't need to give all pirates an equal share and can even select to give some pirates no gold at all). The other pirates can agree or disagree.
If 50% or more pirates agree, the spoils will be divided. If less than 50% agree, the pirate who makes the proposal will be killed and the next pirate can make an offer. (on and on, till the money gets divided).
Rules: Pirates are clever and know that the others are clever as well, so they will make decisions based on their interests and are smart enough to reason out which course of action would be in their best interest: Their interests: - Pirates like gold. They all want to make the most gold they can. - Pirates like to live. - Pirates like others to die, but they prefer gold.
So the riddle has two questions: - Which pirate would be the best to be in this case? - Which offer would you make?
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Post by Dizzy D on Jan 26, 2017 10:14:45 GMT -5
Marvel and Square Enix (specifically Crystal Dynamics, known for Tomb Raider) just announced that they are going to make multiple games together. The first one will be Avengers themed (ReAssembled). Little more than just a teaser trailer (which shows nothing on the game itself), but I'm optimistic as Crystal Dynamics has done some great games and it's about time that Marvel get some decent developer on their games (though the new Spider-Man also has a good developer IIRC).
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Post by Dizzy D on Jan 25, 2017 14:39:54 GMT -5
Added today to the Humble Bundle above (so if you already bought it, log in to download these as well):
Snot Girl #1 Seven to Eternity #1 Paper Girls #1 Monstress #1
Deadly Class Volume 1 Black Science Volume 1
(But they made a mistake in the layout, which they will probably fix soon, but for now Paper Girls is written by O'Malley and Monstress by Vaughan. Well, wouldn't be the first time HumbleBundle left an empty space in their database which leads to other info moved up 1 space.)
Already had Monstress, Seven to Eternity and Monstress and zero interest in Snot Girl, but happy to read Deadly Class and Black Science.
Mini-reviews from last week coming up.
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Post by Dizzy D on Jan 25, 2017 11:39:44 GMT -5
I'm assuming these are beakers and you can only accurately judge them when they are filled till the mark.
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Post by Dizzy D on Jan 25, 2017 5:18:38 GMT -5
Fill Glass4, empty it into Glass 9. > Glass4: 0, Glass9: 4 Fill Glass4, empty it into Glass 9. > Glass4: 0, Glass9: 8 Fill Glass4, empty it into Glass 9. > Glass4: 3. Glass9: 9 Empty Glass9 in sink > Glass4: 3, Glass9: 0 Empty Glass4 in Glass 9 > Glass4:0, Glass9: 3 Fill Glass4, empty it into Glass 9. > Glass4: 0, Glass9: 7 Fill Glass4, empty it into Glass 9. > Glass4: 2, Glass9: 9 Empty Glass9 in sink > Glass4: 2, Glass9: 0 Empty Glass4 in Glass 9 > Glass4:0, Glass9: 2 Fill Glass4, empty it into Glass 9. > Glass4: 0, Glass9: 6
10 steps, but it probably can be done quicker/easier.
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